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階 · 易 · a hierarchy of nulls

The ladder of nulls

A hierarchy of alibis, and what is left to explain at each rung

Tap a rung of the map to see what that null grants and how the four King Wen signatures stand under it.

Saying that an ordering "is not chance" depends on which chance. Here we climb a ladder of conditional nulls, from the free shuffle to the most constrained one, and at each rung we re-evaluate the four known signatures of King Wen. Each null is an alibi granted: it fixes part of the structure and asks what is left to explain.

The map: signatures by rung
transitionalternationquartetsasymmetry
97.53.899.299.9
29.46.289.8const.
31.96.587.7const.
33.210.890.4const.
29.93.3const.const.
17.63.5const.const.

colour = how far the percentile departs from the centre (50) · marked cells are constant: the statistic does not vary under that null

Tap a rung to see what it grants
P1 · pairs

Grants the pair rule: the 32 pairs are permuted as blocks and each is flipped or not. It is the null of the paper.

mean transition distance
29.4
lag-1 autocorrelation (alternation)
6.2
groups of 4 with 12 yang
89.8
within/between-pair asymmetry
constant under this null

observed value: s1 3.3492 · s2 −0.2469 · s3 7 · s4 3.75

What the ladder teaches

Canons and anchors add no explanation. Between P1 and P3 the percentiles barely move: once the pair rule is granted, also knowing that the canons do not mix, or that the four anchors are nailed down, does not change what is left to explain. The pair rule already carries almost everything.

Micro-theorem of invariance

Preserving the quartets preserves the yang sum of each block of four: permuting whole blocks and flipping within a pair does not change how many yang lines the block holds. Since in King Wen 7 of the 16 blocks add up to 12 yang, under P4 and P5 the signature equals 7 in EVERY sample. Its percentile of 0.0 is not an extreme signal: it is the arithmetic of a constant. The quartet signature is a corollary of quartet membership.

yang sum of each block of four, in the received order
1010161210814121212161012121412
The residue at the top

At P5, with the order of the pairs already fixed and only the flips drawn at random, the alternation sits at percentile 3.5, more extreme than the 6.2 of P1: the received orientations alternate more than orientations drawn by lot. This is the residue the ladder does not manage to explain, and it lives in the last degree of freedom left.

Both readings, as the house requires: read on its own, that residue is suggestive; read as the best outcome of a battery of signatures and rungs, it does not survive correction. And it connects with the question of the pair: the same degree of freedom that decides which hexagram opens each pair takes part in the anti-habituation of the distances.

A note on the anchors, which is a lesson about reversal and complement: the four are the pairs whose members are palindromes, which pair by complement out of necessity, because reversing them leaves them unchanged. The shortcut of looking for "a XOR b = 63" catches 8 pairs, not 4: it is also satisfied by four pairs in which reversal and complement coincide (11-12, 17-18, 53-54, 63-64), and those are reversal pairs. Nailing eight instead of four moves rung P3.

20,000 samples per rung, seed 20260722. Percentile = 100 × P(statistic < observed), the house convention. The definitions of the four signatures are the same as in the dialogue with Chan, reused rather than rewritten.

No seal: the originality search for this method is pending. The ladder is a candidate, not a finding.